I encountered this error while using the thinPHP framework is_array function today. You cannot use the return value of a function as an argument
Baidu solution is thinkPHP bug, more reliable said that the PHP version of the problem, 5.4 not, 5.6 is OK, but I use the version of 5.6.
The solution, is_array,empty, is to pass as many variables as possible.
Baidu solution is thinkPHP bug, more reliable said that the PHP version of the problem, 5.4 not, 5.6 is OK, but I use the version of 5.6.
The solution, is_array,empty, is to pass as many variables as possible.
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