. OERROR: [Errno 22] Invalid argument: ‘\u202aD
The following code
file1 = open('D:\watermelon.csv','r')
If you directly copy the path as shown below,
If there is an error, please manually type the path. Modify D–>; d:
file1 = open('d:\watermelon.csv','r')
And then it worked out…
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