You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the ith customer has in the jth bank. Return the wealth that the richest customer has.
A customer’s wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.
Example 1:
Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:
Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation:
1st customer has wealth = 6
2nd customer has wealth = 10
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.
Example 3:
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17
Note:
m == accounts.length
n == accounts[i].length
1 <= m, n <= 50
1 <= accounts[i][j] <= 100
parsing
The sum of the numbers in each row in the table Accounts is the total amount of the user’s deposits.
answer
class Solution(object):
def maximumWealth(self, accounts):
"""
:type accounts: List[List[int]]
:rtype: int
"""
mx = -1
for account in accounts:
mx = max(mx, sum(account))
return mx
# be simple
class Solution(object):
def maximumWealth(self, accounts):
"""
:type accounts: List[List[int]]
:rtype: int
"""
return max(map(sum, accounts))
The results
Runtime: 32 ms, faster than 95.52% of Python online submissions for Richest Customer Wealth.
Memory Usage: 13.6 MB, less than 8.15% of Python online submissions for Richest Customer Wealth.
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